From: Billy Hsu <ruby.maillist@...>
Date: 2007-04-29T23:53:23+09:00
Subject: Re: Array.which_long? ( I coded an extension for Array )

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Thanks for your reply, I learned more on this thread :P
But I have a question:
If I have an array contain:
  ary = [1, 12, 234, "456"]
there has two elements which size is 3, but the longest method just returned
one of them.
I can't solve it :(

thank you, Chris, David, Harry and Robert :D

CFC --

2007/4/29, David A. Black <dblack@wobblini.net>:
>
> Hi --
>
> On 4/29/07, Robert Dober <robert.dober@gmail.com> wrote:
> > On 4/29/07, David A. Black <dblack@wobblini.net> wrote:
> > > You're doing too much work -- let Ruby do it :-)
> > ... for sure, but
> > >
> > >   class Array
> > >     def longest
> > >       map {|e| e.to_s }.max
> > >     end
> > >   end
> > I think it is not exactly what OP wanted
> > because %w{x aaaa}.max is "x"
> > so I will try to comply to his needs
> > def longest
> >     map{ |e| [e.to_s.size, e.to_s]}.max.first
> > end
>
> You're right that I was wrong (because I didn't do the .size thing),
> but yours gives you an integer:
>
> ['x', 'aaaa'].longest  # => 4
>
> I think you'd have to reverse your array. See Harry's code too, which
> uses a block with max.  You could also do:
>
>     sort_by {|e| e.to_s.size }[-1]
>
> (since there's no max_by :-)
>
>
> David
>
> --
> Upcoming Rails training by Ruby Power and Light:
> Four-day Intro to Intermediate
> May 8-11, 2007
> Edison, NJ
> http://www.rubypal.com/events/05082007
>
>


-- 
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