From: Peter Szinek Date: 2007-04-29T21:04:06+09:00 Subject: Partitioning with Set.divide Hello all, I have been playing with partitioning a set recently and I am stuck with an issue. The whole story is here: http://www.rubyrailways.com/partitioning-sets-in-ruby/ A quick version for those who would not like to read the article: Consider this input: a 53 2 3 b 8 62 1 23 a 9 0 31 b 4 45 4 16 7 b 1 23 c 3 42 2 31 4 6 a 1 3 22 a 7 83 1 23 3 b 1 14 4 15 16 2 c 5 16 2 34 the goal is to create a partition based on the character in the first column, i.e.: , , }> Which is exactly what Set.divide does. However, there is one problem: I would like to know if there are duplicate lines. I.e. divide returns the same result, no matter that the input is this: c 5 16 2 34 c 5 16 2 34 c 5 16 2 34 or this: c 5 16 2 34 What I would need is a modified divide which returns also the count of the elements in the input set (at least for those elements which are more than once in the set). Is this doable or do I have to roll some code to do this for me additionally? Cheers, Peter __ http://www.rubyrailways.com :: Ruby and Web2.0 blog http://scrubyt.org :: Ruby web scraping framework http://rubykitchensink.ca/ :: The indexed archive of all things Ruby