From: zswu <wuzongsheng@...>
Date: 2007-04-25T16:25:16+09:00
Subject: Re: URL Splitting

class G
  def send( url, user, pass, code = nil )
    begin
      str = Url.find( url ).url + '?username=' + user + '&password=' + pass.to_s
      str += '&code=' + code.to_s if code
    rescue => e
      if e.is_kind_of RecordNotFoundError
        ...
      end
    end
  end
end

Is this?

On 4/25/07, Mohamed Hussain <pshussain@gmail.com> wrote:
> Hi Dude
> Thank you for your reply
>
> Actually
> i have one table called "urls"
>
> id           url                           params
>
> 1          http://www.mob.com/add.asp     username;password;
> 2          http://www.zad.com/add.asp     username;password;code;
> 3          http://www.mob.com/add.asp     username;
>
>
> These are my table records
>
> I want to get these url and parameters dynamically depending upon id
>
> after i got the value
> i will post the url by Net::HTTP.post_form() method
>
> i can get the record from table but i cannot post the url dynamically
> i want to post the url in a single block.
>
> the username ,password and code are set dynamically
>
> i will call only one function like
> g.send(1,user,pass)
> g.send(2,user,pass,code)
> g.send(3,user)
>
> these three function should call single method,on that method ,we should
> post the url
>
> this is my problem
> can anybody tell me the solution?
>
>
> ok
> Bye
> By
> P.S.Hussain
>
>
>
>
>
>
> --
> Posted via http://www.ruby-forum.com/.
>
>


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