From: Daniel Martin <martin@...>
Date: 2007-04-24T11:34:24+09:00
Subject: Re: Question regarding design of the String Class

One small nit:

"Rick DeNatale" <rick.denatale@gmail.com> writes:

> the expression str[i] is equivalent to *((str) + (i)), it's really a
> pointer to a char, which because of the relationship between arrays
> and pointers in c, can  be interpreted as an array of chars.

No.  str[i] is indeed equivalent to *((str) + (i)), but that's not a
pointer to a char.

((str) + (i)) is a pointer to a char.

*((str) + (i)) is a char.

*((str) + (i)) cannot be interpreted as an array of chars starting i
characters into the original string.

((str) + (i)) could be so interpreted.  ((str) + (i)) is equivalent to
&(str[i]) which is a very different thing from str[i].

-- 
s=%q(  Daniel Martin -- martin@snowplow.org
       puts "s=%q(#{s})",s.map{|i|i}[1]       )
       puts "s=%q(#{s})",s.map{|i|i}[1]