From: Harrison Reiser <y2kbugxp90@...>
Date: 2007-04-09T23:24:43+09:00
Subject: Re: Getting to 100 (#119)



On Apr 9, 6:18 am, "Rick DeNatale" <rick.denat...@gmail.com> wrote:
> On 4/8/07, Marcel Ward <ward...@gmail.com> wrote:
>
> > On 08/04/07, Carl Porth <badc...@gmail.com> wrote:
> > > After going back and reading the current solutions, I like Ken Bloom's
> > > each_partition method.  It's much cleaner than my combinations method.
>
> > I agree, very clean and efficient.  The three lines that put it all
> > together using #zip are what makes this work for me:
>
> > Digits.each_partition(Operators.length+1) do |digitspart|
> >   OperatorPerms.each do |operatorsperm|
> >      expression=digitspart.zip(operatorsperm).flatten.join
> > ...
>
> > I think I would be feeling very happy if I'd submitted this solution :)
>
> May I have the temerity to point out that I posted basically the same
> solution, which I posted two hours before Ken's.
>

Indeed!  Well, isn't too coincidental after all for me to have used
the same mechanism.   Great minds must think alike, no?

Harrison Reiser