From: Rick DeNatale <rick.denatale@...>
Date: 2007-04-09T21:18:16+09:00
Subject: Re: Getting to 100 (#119)

On 4/8/07, Marcel Ward <wardies@gmail.com> wrote:
> On 08/04/07, Carl Porth <badcarl@gmail.com> wrote:
> > After going back and reading the current solutions, I like Ken Bloom's
> > each_partition method.  It's much cleaner than my combinations method.
>
> I agree, very clean and efficient.  The three lines that put it all
> together using #zip are what makes this work for me:
>
> Digits.each_partition(Operators.length+1) do |digitspart|
>   OperatorPerms.each do |operatorsperm|
>      expression=digitspart.zip(operatorsperm).flatten.join
> ...
>
> I think I would be feeling very happy if I'd submitted this solution :)

May I have the temerity to point out that I posted basically the same
solution, which I posted two hours before Ken's.

-- 
Rick DeNatale

My blog on Ruby
http://talklikeaduck.denhaven2.com/