From: Marcel Ward <wardies@...>
Date: 2007-04-09T12:21:25+09:00
Subject: Re: Getting to 100 (#119)

On 08/04/07, Carl Porth <badcarl@gmail.com> wrote:
> After going back and reading the current solutions, I like Ken Bloom's
> each_partition method.  It's much cleaner than my combinations method.

I agree, very clean and efficient.  The three lines that put it all
together using #zip are what makes this work for me:

Digits.each_partition(Operators.length+1) do |digitspart|
  OperatorPerms.each do |operatorsperm|
     expression=digitspart.zip(operatorsperm).flatten.join
...

I think I would be feeling very happy if I'd submitted this solution :)

-- 
Marcel