From: Patrick Hurley <phurley@...>
Date: 2007-03-26T13:10:59+09:00
Subject: Re: how to tranlsate number to binary?

On 3/25/07, Ak 756 <macro.peng@gmail.com> wrote:
> Mike Moore wrote:
>
> > irb(main):008:0> int_to_binary(903)
> > => "001110000111"
>
> Hi ,thanks for advise.
> I want my function to give output 100100000011 for input 903. Where
> '1001','0000','0011' is the binary value for 9,0,3
> Is there efficient way to do this?
>
> --
> Posted via http://www.ruby-forum.com/.
>
>

irb(main):001:0> "903".split(//).map { |c| "%04b" % c }
=> ["1001", "0000", "0011"]
irb(main):002:0> "903".split(//).map { |c| "%04b" % c }.join
=> "100100000011"
irb(main):003:0> "903".split(//).map { |c| "%04b" % c }.join(' ')
=> "1001 0000 0011"
irb(main):004:0>

Something like that I would work,another approach would be to use pack
with an H to then process the resulting string in bits.

pth