From: puzzled186@...
Date: 2001-11-07T13:00:38+09:00
Subject: [ruby-talk:24480] Re: Range in Hash array?

Thanks for the responses.  Of course,  I should have realized that the
1..100 is "just a single object".   I'll play with either approach,
not familiar with the fill method.

Thanks

On Tue, 06 Nov 2001 22:32:57 GMT, "Ryan" <ryan@ryanflynn.com> wrote:

>
>> > I'd like to be able to do something like:
>> > {1..100=>"a",101..300=>"c", 500..1000=>"r"}
>
>Not sure if this does what you want, but it's a possibility:
>
>h=[]
>h.fill('a', 1..100)
>h.fill('c', 101..300)
>h.fill('r', 500..1000)
>
>which would create an array of these elements, filled per
>the range given. this would actually read exactly the same
>way, i.e. h[5] == 'a' and h[301] == nil
>
>Ryan
>