From: eden li <eden.li@...>
Date: 2007-03-18T17:02:43+09:00
Subject: Re: accessing methods from the blocks caller

In the three cases I could think of, "method1" was always available to
the block.  AFAIK, the block you pass to #accept_block no matter where
it is will always be bound to the lexical context you call it in,
meaning that 'method1' will always be available unless you do
something special when you call the block.

Maybe it'll help if you list the source for #accept_block and the
exact error you're getting.

# case 1, 'accept_block' defined in a super class
class S
  def foo; yield; end
end

# case 2, 'accept_block' defined in an included module
module M
  def bar; yield; end
end

# case 3, 'accept_block' defined in some other class
class D
  def baz; yield; end
end

class C < S
  include M
  def m1; 'hi'; end
  def test_foo; foo { m1 }; end
  def test_bar; bar { m1 }; end
  def test_baz; D.new.baz { m1 }; end
end

>> c = C.new
=> #<C:0xb7c396e8>
>> c.test_foo
=> "hi"
>> c.test_bar
=> "hi"
>> c.test_baz
=> "hi"

On Mar 18, 1:30 pm, "andrew" <non...@noname.com> wrote:
> Here's my question... if I have a method that accepts a block and I want to
> call a method of the class I'm in, in that block, how do I do it?  See the
> comment below in the example.  Should make that sentence a bit clearer. :)
>
> class Test
>     def method1
>     end
>
>     def method2
>         accept_block do # accept_block is not part of the Test class
>             ...
>             method1    # I want to call method1 from the class I'm in, but
> I'm getting undefined method for method1
>             ...
>         end
>     end
> end
>
> I understand why I would be getting this error, but I don't know how to fix
> it.  Is there a way to access the caller in the block in order to access the
> method of it?  Kernel.caller is the closest I found, but it's not what I
> want.