From: Robert Dober <robert.dober@...>
Date: 2007-03-17T07:18:53+09:00
Subject: Re: Issues using array.delete within a loop of the same array

On 3/16/07, Fedor Labounko <fedor.labounko@gmail.com> wrote:
> Now this is pure speculation on my part and I'm not offering a solution to
> the problem, rather a likely explanation. The other solutions all look good
> to me as alternatives.
>
> It would make sense that what Array#each is doing behind the scenes is
> simply using an index and a for loop up to the size of the array, and then
> passing you a[i]. So then during the first step you delete a[0], which
> renumbers the elements in the array. During the second step you delete a[1],
> which is now actually 3, since that's now the second element in the array.
> Continue in this manner you'll skip every other element in the array.
Let us see

VALUE
rb_ary_each(ary)
    VALUE ary;
{
    long i;

    for (i=0; i<RARRAY(ary)->len; i++) {
        rb_yield(RARRAY(ary)->ptr[i]);
    }
    return ary;
}

your speculation was correct :) fortuntely i < RARRAY(ary)-> len is
reavaluated after each yield!

Cheers
Robert
>
<snip>


-- 
You see things; and you say Why?
But I dream things that never were; and I say Why not?
-- George Bernard Shaw