From: bob_sidebotham@... (Bob Sidebotham)
Date: 2001-11-04T07:10:45+09:00
Subject: [ruby-talk:24299] yield vs. call?

I'm a bit puzzled whether there is any semantic difference between the
two code fragments, below:

# Example from Programming Ruby
def fibUpTo(max)
  i1, i2 = 1, 1        # parallel assignment
  while i1 <= max
    yield i1
    i1, i2 = i2, i1+i2
  end
end

fibUpTo(1000) { |f| print f, " " }
puts

VS.

# Modified example from Programming Ruby
def fibUpTo(max, blk)
  i1, i2 = 1, 1        # parallel assignment
  while i1 <= max
    blk.call i1
    i1, i2 = i2, i1+i2
  end
end

fibUpTo(1000, proc { |f| print f, " " })
puts

These seem to be equivalent as far as I can tell. Is the original
example just syntactic sugar for the other version, or are there
subtle reasons why a yield statement and magic associated block (I'm
not sure what you call that) is necessary?

Just curious!

Bob Sidebotham