From: sur max <sur.max@...>
Date: 2007-02-16T04:05:23+09:00
Subject: Re: is it behaving strange ?

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if we even consider it this way ....
*a = 9
a << 5
i mean a = [9,5]

and now considering it as...

a # => [9,5]
*a # => 9,5 --- (on assignment)

so the following should be true

b = a # => [9,5] ----- true
b = *a # => [9,5] ----- true , b is re-wrapping 9,5 as [9,5]
b = [a,6] # => [[9,5],6] ---- true, naturally
b = [*a,6] # => [9,5,6] ----- false,  compile error
b = *a,6 # => [9,5,6]  ----- false, compile error


On 2/16/07, dblack@wobblini.net <dblack@wobblini.net> wrote:
>
> Hi --
>
> On Fri, 16 Feb 2007, Jacob Fugal wrote:
>
> > On 2/15/07, sur max <sur.max@gmail.com> wrote:
> >> *a = 9  # i like this number :)
> > ...
> >> a << 5
> >> b = *a # => [9,5] ------- an Array
> >> here it seems false "*x equals [x] without the []"
> >
> > Actually, the "rule" still applies, in that:
> >
> > b = *a # where a = [9, 5]
> >
> > and
> >
> > b = 9, 5
> >
> > Have the same effect. You were just forgetting to consider that b
> > would just slurp them back into an array.
> >
> >> *a # => compile error
> >
> > This seems to be the only remaining "anomaly".
>
> It isn't, though:
>
> irb#1(main):017:0> a = [9,5]
> => [9, 5]
> irb#1(main):018:0> *a
> SyntaxError: compile error
> (irb#1):18: syntax error
>          from (irb#1):18
> irb#1(main):019:0> 9,5
> SyntaxError: compile error
> (irb#1):19: syntax error
>          from (irb#1):19
>
>
> David
>
> --
> Q. What is THE Ruby book for Rails developers?
> A. RUBY FOR RAILS by David A. Black (http://www.manning.com/black)
>     (See what readers are saying!  http://www.rubypal.com/r4rrevs.pdf)
> Q. Where can I get Ruby/Rails on-site training, consulting, coaching?
> A. Ruby Power and Light, LLC (http://www.rubypal.com)
>
>


-- 
sur
http://expressica.com

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