From: Robert Dober <robert.dober@...>
Date: 2007-02-14T02:56:11+09:00
Subject: Re: One-Liners (#113)

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On 2/13/07, James Edward Gray II <james@grayproductions.net> wrote:
>
> On Feb 13, 2007, at 11:10 AM, Ken Bloom wrote:
>
> >>>> Hash.new{|h, n| n==1 ? [1] : [n] + h[n%2 == 0 ? n/2 : n*3+1] }
> >>>> [quiz]
> >>> Kudos on the memoizing wondrous number, btw. :)
> >> It's not actually.  I never assign the Hash value.  ;)
> >
> > So it's equivalent to:
> > (h=lambda {|n| n==1 ? [1] : [n] + h[n%2 == 0 ? n/2 : n*3+1] })[23]
>
> Exactly.
>
> James Edward Gray II


That really puts the spotlight on it,  this will go away  in  2.0 though if
I understand correctly :) and one would need to write:

(h=lambda {|n,lmb| n==1 ? [1] : [n] + h[n%2 == 0 ? n/2 : n*3+1,lmb] })[23,h]


is that right?

Robert

-- 
We have not succeeded in answering all of our questions.
In fact, in some ways, we are more confused than ever.
But we feel we are confused on a higher level and about more important
things.
-Anonymous

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