From: Edwin Fine <efine145-nospam01@...>
Date: 2007-02-13T15:24:39+09:00
Subject: Re: What is Proc#==

Here's the C code for proc_eq (in eval.c). It seems that the procs have 
to either be the same object, or failing that have the same type 
(T_DATA), class, body, variables, scope, in-block local variables 
(dyna_vars), and flags.

static VALUE
proc_eq(self, other)
    VALUE self, other;
{
    struct BLOCK *data, *data2;

    if (self == other) return Qtrue;
    if (TYPE(other) != T_DATA) return Qfalse;
    if (RDATA(other)->dmark != (RUBY_DATA_FUNC)blk_mark) return Qfalse;
    if (CLASS_OF(self) != CLASS_OF(other)) return Qfalse;
    Data_Get_Struct(self, struct BLOCK, data);
    Data_Get_Struct(other, struct BLOCK, data2);
    if (data->body != data2->body) return Qfalse;
    if (data->var != data2->var) return Qfalse;
    if (data->scope != data2->scope) return Qfalse;
    if (data->dyna_vars != data2->dyna_vars) return Qfalse;
    if (data->flags != data2->flags) return Qfalse;

    return Qtrue;
}

The only way so far that I have been able to create two equal procs that 
have different object IDs is to clone or dup them. I am sure there must 
be another way using some metaprogramming, but I am not experienced 
enough in Ruby to find it easily (or maybe ever:)

irb(main):001:0> a = lambda { 4 }
=> #<Proc:0x00002b8dd669e828@(irb):1>
irb(main):002:0> b = a.clone
=> #<Proc:0x00002b8dd669e828@(irb):1>
irb(main):003:0> a.object_id
=> 23944093823940
irb(main):004:0> b.object_id
=> 23944093815980
irb(main):005:0> a == b
=> true


-- 
Posted via http://www.ruby-forum.com/.