From: Jeremy McAnally <jeremymcanally@...>
Date: 2007-02-13T00:06:10+09:00
Subject: Re: embedding if statements in upto function.(newbie question)

Let's clean your syntax up a little bit first...

0.upto(a.size - 2) do |i|
  if (a[i][2]==a[i+1][2] and a[i][0]==a[i+1][0])
    print  ((a[i+1][3] - a[i][3]) / a[i][3] * 100) / n
  else
    print 0
  end
end

Looking at this, I (as someone else already stated) would make sure
that everything is a number rather than a string.  It seems that if
you're having problems with the if statement, that's probably the
case.  I would inspect the objects at every iterations (e.g., rather
than just printing 0, I would print a[i][2].inspect and
a[i+1][2].inspect or whatever).  That should give you some insight as
to what's going on.

--Jeremy

On 2/12/07, Michael Sc <michael.schatzow@gmail.com> wrote:
> Thank you to everyone for all of your help.
> I was trying to use upto to go through an array of arrays while using if
> statments.  Could anyone enlighten me on what I am doing wrong with the
> if statements?
> I am sure it is something easy.
>
> I tried this:
> 0.upto( a.size-2 ) {|i|
>   if (a[i][2]==a[i+1][2] and a[i][0]==a[i+1][0]) then
>     print { (a[i+1][3] - a[i][3]) / a[i][3] * 100 } /n
> else print 0
> end}
>
> Thanks again for all of the help.
> Michael
>
> --
> Posted via http://www.ruby-forum.com/.
>
>


-- 
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