From: Phrogz <gavin@...>
Date: 2007-02-09T08:00:11+09:00
Subject: Re: How to "pass" the current binding's block to some other method?

On Feb 8, 3:52 pm, "Lyle Johnson" <lyle.john...@gmail.com> wrote:
> Suppose I have a method that will yield to a block if one is given:
>
>     def try(x, y, z)
>       # ... do some other stuff first ...
>       yield self if block_given?
>     end
>
> Now suppose that I create an alias to this method, for the purpose of
> overriding how it's called, e.g.
>
>     alias old_try try
>     def try(hash)
>       old_try(hash[:x], hash[:y], hash[:z])
>     end
>
> If someone calls this new and improved version of try() and provides a
> block, is there any way for me to somehow pass that block down into
> old_try() without actually modifying the method signature?

Do you feel that this:
  def try( hash, &block )
    old_try( hash[:x],hash[:y],hash[:z],&block )
  end
is somehow changing its signature? (You can still choose to pass a
block or not.)