From: Emmanuel <oga_emmanuel_oga@...>
Date: 2007-01-29T23:39:21+09:00
Subject: Short solution for replacing Strings inside a file?

Hello, i'm working with ruby 1.8.5 on a Suse SLES 9 Linux machine.

I need to replace strings inside files, specifically the string
FECHAIMPRE
with the current date. I had a bash script that looked like this:

BOF#################################################################
    date=`date '+%d:%m:%y'`
    for item in `ls /u/sag/impresion/PRODISAA/etiquetas/lpt28*.tmp`
    do
       sed -e s/FECHAIMPRE/$date/g < $item > $item.po
       mv $item.po $item
    done
EOF#################################################################


And i wanted to rewrite it in ruby. I came up with this:


#BOF#################################################################
$fecha= Time.now.strftime("%d/%m/%Y")

def UpdateDates(file)

    filename= file.to_s

    # Rename "file" to "file.temp"
    FileUtils.mv(filename, filename + ".temp")

    # Create "file" file
    File.open(filename, "w") do |out|

        # Write in "file" the modified "file.temp" lines.
        IO.foreach(filename + ".temp") do |line|

            if line =~ /FECHAIMPRE/
                line.gsub!(/FECHAIMPRE/, $fecha)
            end

            out << line
        end

    end

    # Erase the temporal
    FileUtils.rm(filename + ".temp", :force => true)
end

Dir.glob("*.tmp").each { |file| UpdateDates(file) }

#EOF#################################################################

But i keep thinking there has to be a shorter way. I read the ruby
documentation
for IO and File classes but i haven't found any better solution.

What do you think about it???

Thanks!

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