From: Erik Veenstra <erikveen@...>
Date: 2007-01-29T05:28:59+09:00
Subject: "a string".xor("another string")

I want to do an XOR of two strings:

 "a string".xor("another string")

It's not that hard to implement, but it's not fast either,
since it walks through the data string, byte-by-byte.

Any ideas? For example: "It's memory-hungry!". Any solutions?

gegroet,
Erik V. - http://www.erikveen.dds.nl/

----------------------------------------------------------------

 class String
   def xor(other)
     if other.empty?
       self
     else
       a1        = self.unpack("c*")
       a2        = other.unpack("c*")

       a2 *= 2   while a2.length < a1.length

       a1.zip(a2).collect{|c1,c2| c1^c2}.pack("c*")
     end
   end
 end

----------------------------------------------------------------