From: Jeremy McAnally <jeremymcanally@...>
Date: 2007-01-08T14:50:41+09:00
Subject: Re: Grouping elements of an array?

class Array
  def group_in(how_many)
   ret_array = []
   new_array = []
	 self.each {|elem| how_many.times { new_array << self.shift };
ret_array << new_array; new_array = []; }
   ret_array
  end
end

x = [1,2,3,4,5,6,7,8,9]
x = x.group_in(3)
require 'pp'
pp x

>> [[1, 2, 3], [4, 5, 6], [7, 8, 9]]

That should do it. :)  Not sure if it's the best way, but it will work.

--Jeremy

On 1/8/07, Sam Kong <sam.s.kong@gmail.com> wrote:
> Hello,
>
> What's the best way to do the following?
>
> [1,2,3,4,5,6,7,8,9] => [[1,2,3],[4,5,6],[7,8,9]]
>
> I want to transform the array into an array of arrays with fixed number
> of elements.
> I think there should be a method but I can't find it.
>
> I can iterate the elements using a counter to divide but it's so
> boring.
>
> Thanks in advance.
>
> Sam
>
>
>


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