From: Mark Woodward <markonlinux@...>
Date: 2007-01-04T08:00:07+09:00
Subject: Re: Array questions

Hi Ken,

Kenosis wrote:
> All I can think of is this: the author of the maze code wanted to
> ensure that the initial value of @paths was assured to be an empty
> array.  If he/she resorted to Array.new's default argument, which could
> change then @path might not be in the state the programmer expected.
> Other than that, as you surimised, the 3 ways you initialized the array
> should all result in the same thing, AFAIK.
>
> Ken

I suspected that but I couldn't understand how/why this could be done
with a size 0.

@paths = Array.new(0,Array.new(0)) to me reads as "create a new array
with nothing in it and make that nothing reference another empty
array?"
ie []

@paths = Array.new(1,Array.new(0)) This, if my logic's right, reads as
"create a new array with a single element that's an empty array.
ie [[] ]

Are you saying that even though @paths is created as an empty array, it
expects the first element it gets to be an array? If not it will throw
an error?
Sorry, I can't check this in irb ATM. 


cheers,

-- 
Mark