From: Robert Klemme <shortcutter@...>
Date: 2006-12-14T06:55:05+09:00
Subject: Re: How to overload the operator !=?

On 13.12.2006 20:33, Tom Werner wrote:
> And upon reflection, this makes sense, as in any sane world !(f1 == f2) 
> will equal (f1 != f2), and so redefining != would be redundant.

It's been a long day and I'm not sure whether my logic fails me here, 
but - from the above seems to follow that C++ is potentially insane. 
Not that I didn't know that before - but it's a nice outcome of a thread 
about operators. :-)

	robert