From: Edwin Fine Date: 2006-12-09T15:57:30+09:00 Subject: Re: Array changing after concat function unknown wrote: > Logan Capaldo wrote: > >> > > >> puts one.inspect >> > > results in tempArr still having the values originally assigned to array >> > if you cut off one Fido's legs (modify one[0]), that leg on my Fido >> > (tempArr[0]) is also cut off, because they are the same Fido. >> > >> > m. >> > >> That is the most disturbed, and yet apt analogy ever > > Clearly you've never read any of my books. > >> Mind if I quote you? > > Woof! (That means "Be my guest.") m. (Off-topic to Matt) The best languages are dead languages? Did I translate that correctly? -- Posted via http://www.ruby-forum.com/.