From: Brian <wizard.rb@...>
Date: 2006-12-08T20:23:53+09:00
Subject: Re: Calling super in overwritten methods

Hey,
Assuming your trying to make a determination in class B as to which
method to use, you could make method2 a class method.

class A
  def method1
    A.method2
  end

  def self.method2
    return 100
  end
end

class B < A
  def method1
    x = 1
    puts A.method2 if x == 1 # => 100
    puts method2 if x == 2 # => 200
  end

  def method2
    return 200
  end
end

B.new.method1

- Brian

On Dec 6, 5:36 am, Joerg Diekmann <joe...@pobox.com> wrote:
> Hi - not sure if this is possible - but it feels like it could be with
> some serious ruby-fu.
>
> I have the following:
>
> class A
>   def method1
>     method2
>   end
>
>   def method2
>     return 100
>   end
> end
>
> class B < A
>   def method1
>     super
>   end
>
>   def method2
>     return 200
>   end
> end
>
> This is what happens:
>
> b.method1 # 200
>
> But, what I want is:
>
> b.method1 # 100
>
> Is this possible at all?
> 
> Thanks
> Joerg
> 
> --
> Posted viahttp://www.ruby-forum.com/.