From: Mikkel Bruun <mikkel.bruun@...>
Date: 2001-10-17T23:42:36+09:00
Subject: [ruby-talk:22674] SV:  Re: blocks in C??? (and hi guys)

Thanks a lot...

However, being a c newbie i dont really understand the syntax of this
specific API call...

So here is how I see it,


i want to perform the following urby code 

obj.method(parm1){
|retval1|
	dostuff(retval1)
}

using the specified API call I would have to pull the block out, making a
function with the following signature:
	block(reval1)

so now that I have identified the two funcs specified in the API call., my
call would be like below 

rb_iterate(method(), parm1, dostuff(), 0)

or???

it doesnt look right, and my C skills is not adequate...
could someone please show me how to translate the ruby code into c???


thanks in advance

  Mikkel Bruun


> -----Oprindelig meddelelse-----
> Fra: ts [mailto:decoux@moulon.inra.fr]
> Sendt: 17 October 2001 14:59
> Til: ruby-talk@ruby-lang.org
> Cc: ruby-talk@ruby-lang.org
> Emne: [ruby-talk:22671] Re: blocks in C??? (and hi guys)
> 
> 
> >>>>> "M" == Mikkel Bruun <mikkel.bruun@valtech.dk> writes:
> 
> M> im writing a c extension to ruby, and I have to call a 
> method defined in a
> M> ruby class. however, the method needs to be passed a block...
> 
> M> How do i pass a block i c???
> 
>  rb_iterate(), you have in README.EXT
> 
>  VALUE rb_iterate(VALUE (*func1)(), void *arg1, VALUE 
> (*func2)(), void *arg2)
> 
>  Calls the function func1, supplying func2 as the block.  
> func1 will be
>  called with the argument arg1.  func2 receives the value 
> from yield as
>  the first argument, arg2 as the second argument.
>  
> 
> 
> Guy Decoux
>