From: Phil Tomson <rubyfan@...>
Date: 2006-11-11T03:41:09+09:00
Subject: Re: accessing caller's binding implicitly

On 11/9/06, Ben Bleything <ben@bleything.net> wrote:
> Hi all,
>
> As part of my IRB shell history hack (shameless plug[1]), I need to be
> able to access the caller's binding.  Essentially, I need to be able to
> do this:
>
>    def irb_eval( lines, scope )
>      eval(lines.join("\n"), scope)
>    end
>
>    irb_eval( ['a = :foo', 'b = :bar'], binding )
>
> ... but without explicitly passing the binding.  The goal is this:
>
>    irb_eval( ['a = :foo', 'b = :bar'] )
>
>    puts a
>    => :foo
>
>    puts b
>    => :bar
>
> Is this even possible?  As it is, the eval happens inside of irb_eval's
> scope (I'm assuming... wherever it happens, I can't see the results when
> it's done) which puts a cramp in my plans for world domination via cute
> IRB hacks.
>
> Help?
>
> Thanks,
> Ben
>
> [1]: http://blog.bleything.net/articles/2006/10/21/shell-style-history-for-irb
>
>

Ben,

I was thinking about this when you asked at the meeting the other night...

Given that binding_of_caller seems to be broke in 1.8.5, would
something like this work for you?:

class IRB_Evaler
    def initialize scope
      @scope = scope
    end
     def irb_eval(lines)
       eval(lines.join("\n"),@scope)
     end
  end
  evaler = IRB_Evaler.new binding
  evaler.irb_eval( ['a = :foo', 'b = :bar'] )
  puts a  #=> foo

Phil