From: Jim Freeze <jim@...>
Date: 2006-10-31T05:58:14+09:00
Subject: Re: __FILE__ for requiring file

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Just make sure that you won't have any file names with a ':' in them =)

Sure:

  __REQUIRING_FILE__ =  caller.grep(/^(.*):\d+(?::in)?$/)[0]



-- 
Jim Freeze

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