From: Phrogz <gavin@...>
Date: 2006-10-28T00:30:10+09:00
Subject: Re: a regex

Alexandru Popescu wrote:
> Thanks for all suggestions, but the requirement is to be done thru
> regex only :-). I knew how to do it with split, but I need to do it
> with regexps only.

I'm unclear on what your real requirements are, but here are some
possible alternatives:

s = "2006%2F10%2Fasdfasdf"
p s.scan( /.+?(?=%2F|$)/ ).map{ |v| v.gsub( '%2F', '' ) }
#=> ["2006", "10", "asdfasdf"]

p s.gsub( '%2F', "\n" ).scan( /[^\n]+/ )
#=> ["2006", "10", "asdfasdf"]

p s.match( /^(.+?)%2F(.+?)%2F(.+?)$/ ).to_a
#=> ["2006%2F10%2Fasdfasdf", "2006", "10", "asdfasdf"]