From: Alexandru Popescu <the.mindstorm.mailinglist@...>
Date: 2006-10-28T00:11:26+09:00
Subject: Re: a regex

On 10/27/06, Robert Klemme <shortcutter@googlemail.com> wrote:
> On 27.10.2006 16:39, Chris Gernon wrote:
> > Alexandru Popescu wrote:
> >> Thanks for all suggestions, but the requirement is to be done thru
> >> regex only :-). I knew how to do it with split, but I need to do it
> >> with regexps only.
> >
> > How about just:
> >
> > irb(main):001:0> match = '2006%2F10%2Fasdfasdf'.match
> > /^(.*)%2F(.*)%2F(.*)$/
> > => #<MatchData:0x1cf404>
> > irb(main):002:0> match[1]
> > => "2006"
> > irb(main):003:0> match[2]
> > => "10"
> > irb(main):004:0> match[3]
> > => "asdfasdf"
>
> This has a potential for disastrous backtracking with large strings.
> This one is better - if you can guarantee there there is no "%" besides
> the one preceding the "2F":
>
> => "2006%2F10%2Fasdfasdf"
>  >> s.match(/^([^%]*)%2F([^%]*)%2F(.*)$/).to_a
> => ["2006%2F10%2Fasdfasdf", "2006", "10", "asdfasdf"]
>
> Or maybe even
>
>  >> s.match(/^((?>[^%]*))%2F((?>[^%]*))%2F((?>.*))$/).to_a
> => ["2006%2F10%2Fasdfasdf", "2006", "10", "asdfasdf"]
>
> :-)
>

Yep... this is the closest I got too :-).

./alex
--
.w( the_mindstorm )p.

> Kind regards
>
>         robert
>
>
>