From: Jon Lim <snowblink@...>
Date: 2006-10-27T23:39:21+09:00
Subject: Re: a regex

s = "2006%2F10%2Fasdfasdf"
year,month,other = URL.decode(s).split(/\//)

On 27/10/06, Alexandru Popescu <the.mindstorm.mailinglist@gmail.com> wrote:
> Hi!
>
> I have a string in the following form: 2006%2F10%2Fasdfasdf (or more
> generic: any_characters+%2Fany_characters+%2Frest_of_it). I am
> wondering if I can retrieve the groups 2006, 10, asdfasdf thru a regex
> (I confess I couldn't figure it out so far :-( ).
>
> many thanks,
>
> ./alex
> --
> .w( the_mindstorm )p.
>
>


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