From: matz@... (Yukihiro Matsumoto)
Date: 2001-10-07T22:00:32+09:00
Subject: [ruby-talk:22194] Re: Match expressions

Hi,

In message "[ruby-talk:22163] Re: Match expressions"
    on 01/10/07, Alan Moore <alan_moore@gmx.net> writes:

|So, given the expression "node1 =~ node2", if node1 is a literal 
|regex (i.e., /xyz/ or %{xyz}), Ruby translates the expression to  
|"node1.=~(node2)".  If node2 is a literal regex, and node1 evaluates 
|to a string, Ruby does a "node2.=~(node1)".  In both cases, it calls 
|the rb_reg_match function directly, as a speed optimization.  But if 
|node1 doesn't evaluate to a string, Ruby turns it around again and 
|does a "node1.=~(node2)", under the assumption that node1 is a user-
|defined object that defines its own "=~" method.
|
|Is that right?  Is that what you meant, Guy?

Yes.  And it's just an ugly hack.  I don't think you have to follow.

							matz.