From: Rick DeNatale <rick.denatale@...>
Date: 2006-10-21T01:13:26+09:00
Subject: Re: How to the output in 12x8 format

On 10/19/06, Tim Pease <tim.pease@gmail.com> wrote:
> On 10/19/06, Li Chen <chen_li3@yahoo.com> wrote:
> > Hi folks,
> >
> > I have an array containing 96 elements. I want to print the array in
> > 12x8 format. Any comments?
> >
> > Thanks in advance,
> >
> > Li
>
> require 'enumerator'
>
> ary = (1..96).to_a
> ary.each_slice(8) {|slice| puts slice.inspect}
>
> [1, 2, 3, 4, 5, 6, 7, 8]
> [9, 10, 11, 12, 13, 14, 15, 16]
> [17, 18, 19, 20, 21, 22, 23, 24]
> [25, 26, 27, 28, 29, 30, 31, 32]
> [33, 34, 35, 36, 37, 38, 39, 40]
> [41, 42, 43, 44, 45, 46, 47, 48]
> [49, 50, 51, 52, 53, 54, 55, 56]
> [57, 58, 59, 60, 61, 62, 63, 64]
> [65, 66, 67, 68, 69, 70, 71, 72]
> [73, 74, 75, 76, 77, 78, 79, 80]
> [81, 82, 83, 84, 85, 86, 87, 88]
> [89, 90, 91, 92, 93, 94, 95, 96]

Or as an alternative:

ary = (1..8).to_a
(0..7).each {|i| p ary[i*8, 8] }

One advantage of Tim's suggestion of using each_slice is that the data
doesn't really need to be an array, it can be another class which
mixes in Enumerable.

require 'enumerator'
not_really_array = (1..96)
not_really_array.each_slice(8) { |slice| p slice }

[1, 2, 3, 4, 5, 6, 7, 8]
[9, 10, 11, 12, 13, 14, 15, 16]
[17, 18, 19, 20, 21, 22, 23, 24]
[25, 26, 27, 28, 29, 30, 31, 32]
[33, 34, 35, 36, 37, 38, 39, 40]
[41, 42, 43, 44, 45, 46, 47, 48]
[49, 50, 51, 52, 53, 54, 55, 56]
[57, 58, 59, 60, 61, 62, 63, 64]
[65, 66, 67, 68, 69, 70, 71, 72]
[73, 74, 75, 76, 77, 78, 79, 80]
[81, 82, 83, 84, 85, 86, 87, 88]
[89, 90, 91, 92, 93, 94, 95, 96]

-- 
Rick DeNatale

My blog on Ruby
http://talklikeaduck.denhaven2.com/