From: Farrel Lifson <farrel.lifson@...>
Date: 2006-10-20T23:37:08+09:00
Subject: Re: break from block

On 20/10/06, Robert Klemme <shortcutter@googlemail.com> wrote:
> On 20.10.2006 15:45, Farrel Lifson wrote:
> > I've just run into the following problem. Doing this:
> > block = lambda{|i| i > 5 ? break : nil}
> >  n.times &block
> > raises a LocalJumpError, I assume because break is not valid from
> > within a Proc object. Is there any way to get around this?
>
> The direct form works.
>
> irb(main):008:0> 10.times {|i| p i; break if i > 5}
> 0
> 1
> 2
> 3
> 4
> 5
> 6
> => nil
>
> Hm, at the moment I do not have an idea.  What do you need that for?
> Maybe there is a different solution.  For example:
>
> irb(main):009:0> crit = lambda {|i| i > 5}
> => #<Proc:0x00395698@(irb):9>
> irb(main):010:0> 10.times {|i| p i; break if crit[i]}
> 0
> 1
> 2
> 3
> 4
> 5
> 6
> => nil
>
> Cheers
>
>         robert

I'm just trying to optimise some code and I was wondering if doing
  block = lambda{|i| #processing; if i > 5; break}
  n.times &block
would be any faster than doing it directly.

Farrel