From: Farrel Lifson <farrel.lifson@...>
Date: 2006-10-20T23:23:11+09:00
Subject: Re: break from block

On 20/10/06, Michael Studman <me@michaelstudman.com> wrote:
> I'm not sure it's the Ruby way (I'm too new to Ruby to judge) but how
> about:
>
> block = lambda{|i| i > 5 ? throw(:enough) : nil}
> n = 10
>
> catch(:enough) do
>    n.times &block
> end
>
>
> > I've just run into the following problem. Doing this:
> > block = lambda{|i| i > 5 ? break : nil}
> >  n.times &block
> > raises a LocalJumpError, I assume because break is not valid from
> > within a Proc object. Is there any way to get around this?
> >
> > Farrel
> >
> >

I tried that but it's a performance killer (nearly 3 times as slow in
my informal testing), which I'm trying to optimise for atm.

Farrel