From: Josselin <josselin@...>
Date: 2006-10-20T20:50:08+09:00
Subject: Re: filling an array excepted first and last position...

On 2006-10-20 10:54:24 +0200, "Tomasz Wegrzanowski" 
<tomasz.wegrzanowski@gmail.com> said:

> On 10/20/06, Josselin <josselin@wanadoo.fr> wrote:
>> ldom =  30  # variable (last day of a month...)
>> 
>> # array init to 0
>>   @obk = []
>>   1.step(ldom, 1) do |i|
>>     @obk[i] = 0
>>   end
>> 
>> I am filling an array as follows  (part of a larger filling scheme) :
>> ----
>> #fiiling the array upon another array content
>> # but I'd like to AVOID filling the first and last position in this loop....
>>     obdays.each do |bd|
>>         @obk[bd] = 1
>>     end
> 
> How about:
> @obk = Array.new(ldom, 0)
> obdays[1..-2].to_a.each{|bd| @obk[bd] = 1}

interesting but when I enter this command  obdays is already a range :

> obdays = >  2..6
so I want to do someting like that :
	obdays[3..5].to_a.each{|bd| @obk[bd] = 1}
starting  the position after the first in the range and ending with the 
position before the last
like   obdays[start+1..end-1].to_a.each{|bd| @obk[bd] = 1}
?

> 
> to_a just in case obdays is empty, in which case obdays[1..-2] return nil.
> I don't know why Array#[] with a range cannot just always return [].
> 
> And don't worry about creating a new object,
> obdays and obdays[1..-2] actually share storage.