From: Robert Klemme <shortcutter@...>
Date: 2006-10-20T20:45:07+09:00
Subject: Re: filling an array excepted first and last position...

On 20.10.2006 13:35, Josselin wrote:
> On 2006-10-20 10:32:18 +0200, Robert Klemme <shortcutter@googlemail.com> 
> said:
> 
>> On 20.10.2006 09:59, Josselin wrote:
>>> ldom =  30  # variable (last day of a month...)
>>>
>>> # array init to 0
>>>  @obk = []
>>>  1.step(ldom, 1) do |i|
>>>    @obk[i] = 0
>>>  end
>>
>> @obk = Array.new(ldom, 0)
> better  ,  avoiding @obk[0] = nil ...
>>
>>> I am filling an array as follows  (part of a larger filling scheme) :
>>> ----
>>> #fiiling the array upon another array content
>>> # but I'd like to AVOID filling the first and last position in this 
>>> loop....
>>>    obdays.each do |bd|
>>>        @obk[bd] = 1
>>>    end
>>> ------
>>> # ajusting first and last position (in the larger scheme)
>>>    @obk[obdays.first] += -1
>>>    @obk[obdays.last] += -2
>>
>> I am not exactly sure what problem you have with this approach.  Here 
>> is a different one
>>
>> obdays.each_with_index do |bd, idx|
>>    case idx
>>      when 0
>>        # ignore, @obk[bd] is 0 already
>>      when obdays.length - 1
>>        # set to 1 + (-2) = -1
>>        @obk[bd] = -1
>>      else
>>        @obk[bd] = 1
>>    end
>> end
>>
>> Does that help?
>>
>>     robert
> 
> yes and no, I cannot test @obk[bd] == 0 as it may change....  as 
> indicated in one of my response post

??? There is no test for @obk[bd] == 0 in the code above.  It's a bit 
difficult to guess what you really want with the information I have seen.

Cheers

	robert