From: Jani Patokallio Date: 2006-10-09T20:58:09+09:00 Subject: gsub and slash-ampersand in the substitution string Greetings, I'm trying to do something that should be very simple: stick a "\" in front of every instance of "&" in a string. However, the obvious code... "this&that".gsub!("&", "*") --> "this*that" # OK! "this&that".gsub!("&", "\\&") --> "this&that" # Wrong ...doesn't work, because "\&" means "last match" in gsub substitution strings. How can I escape this? I experimentally determined that entering "\\\\\\&" (that's six backslashes) gets the desired result, but I don't really understand why. Is there a less obscure way of doing this? Cheers, -jani -- Posted via http://www.ruby-forum.com/.