From: Eero Saynatkari Date: 2006-09-03T05:13:35+09:00 Subject: Re: yielding a block to another block Eero Saynatkari wrote: > David Chelimsky wrote: >> Hi all, >> >> The mocking framework in rspec uses method_missing to capture all the >> messages sent to it, comparing the message to a list of expected >> messages. For various reasons I'm trying to rework this so that >> instead of using method_missing, we define the expected message on the >> mock on the fly. >> >> For that to happen, setting expectations on the mock ends up invoking >> this: >> >> def define_expected_method(sym) >> (class << self; self; end).__send__(:define_method, sym, >> lambda {|*args| message_received(sym, *args)}) >> end >> >> The Proc yields *args, which are then passed to message_received. How >> can I get the Proc to yield a block that is passed in with the call to >> :sym? I tried this: >> >> lambda {|*args, &block| .... >> >> but it throws an error. Any other ideas? Let me know if the question >> is not clear. > > You cannot currently do that with a block (1.9 and 2.0 will > allow &block arguments). In the meanwhile, you can #eval the > method into existence instead: > > def define_expected_method(sym) > class << self; self; end.__send__ :class_eval, %{ > def #{sym}(*args, &block) > message_received sym, *args, &block # ? > end > } > end # One of these days.. *sigh* def define_expected_method(sym) class << self; self; end.__send__ :class_eval, %{ def #{sym}(*args, &block) message_received :#{sym}, *args, &block # ? end } end > >> Thanks, >> David -- Posted via http://www.ruby-forum.com/.