>From: David Alan Black

>Reply-To: ruby-talk@ruby-lang.org

>To: ruby-talk@ruby-lang.org (ruby-talk ML)

>Subject: [ruby-talk:21053] Re: @aHash{A..Z} = (0..25);

>Date: Tue, 11 Sep 2001 12:18:22 +0900

>Hello --

>On Tue, 11 Sep 2001, Dat Nguyen wrote:

> > How to write the following Perl code in Ruby:

> >

> > @aHash{A..Z} = (0..25);

>One possibility, drawn from some Ruby Behaviors experiments:

> class Hash

> alias :oldset :[]=

> def []=(ks,vs)

> ks.to_a.each_with_index do |k,i|

> oldset(k,vs.to_a[i])

> end

> c = {}

> c['A'..'Z'] = 0..25

>(One of my main incentives for working on Ruby Behaviors has

>always been to get more back-and-forth going between arrays (or

>ranges) and hashes.)

>David

>--

>David Alan Black

>home: dblack@candle.superlink.net

>work: blackdav@shu.edu

>Web: http://pirate.shu.edu/~blackdav

Study all solutions so far, I also come up with the following:

class Hash

def Hash.array_array (index, value)

aHash = {}

index.each { |ind| aHash[ind] = value[index.index(ind)] }

aHash

end

aHash = Hash.array_array(('A'..'Z').to_a, (0..25).to_a)

This would declare and initialize a Hash out of any two parallel Arrays.

Dat