From: ptkwt@...1.aracnet.com (Phil Tomson)
Date: 2001-09-11T21:22:36+09:00
Subject: [ruby-talk:21100] Re: @aHash{A..Z} = (0..25);

Admittedly, for this particular type of thing, perl does a lot of work for 
you.

This is the Ruby solution I came up with - anybody got anything shorter?

aHash = Hash.new
valArray=(0..25).to_a
('A' .. 'Z').each { |key|
   aHash[key] = valArray.to_a.shift
} 

Phil

In article <F113T9EVP9BOJQvtMFW0000e231@hotmail.com>,
Dat Nguyen <thucdat@hotmail.com> wrote:
><html><div style='background-color:'><DIV>
><P>How to write the following Perl code in Ruby:</P>
><P>@aHash{A..Z} = (0..25);</P>
><P>Thanks,</P>
><P>Dat</P></DIV></div><br clear=all><hr>Get your FREE download of MSN
>Explorer at <a
>href='http://go.msn.com/bql/hmtag_itl_EN.asp'>http://explorer.msn.com</a><br></html>
>
>