From: David Alan Black <dblack@...>
Date: 2001-09-11T12:18:22+09:00
Subject: [ruby-talk:21053] Re: @aHash{A..Z} = (0..25);

Hello --

On Tue, 11 Sep 2001, Dat Nguyen wrote:

> How to write the following Perl code in Ruby:
>
> @aHash{A..Z} = (0..25);

One possibility, drawn from some Ruby Behaviors experiments:

  class Hash
    alias :oldset :[]=
    def []=(ks,vs)
      ks.to_a.each_with_index do |k,i|
        oldset(k,vs.to_a[i])
      end
    end
  end

  c = {}
  c['A'..'Z'] = 0..25


(One of my main incentives for working on Ruby Behaviors has
always been to get more back-and-forth going between arrays (or
ranges) and hashes.)


David

-- 
David Alan Black
home: dblack@candle.superlink.net
work: blackdav@shu.edu
Web:  http://pirate.shu.edu/~blackdav