From: Joseph McDonald <joe@...>
Date: 2001-09-11T07:27:34+09:00
Subject: [ruby-talk:21048] Re: @aHash{A..Z} = (0..25);


DN> How to write the following Perl code in Ruby:

DN> @aHash{A..Z} = (0..25);

not sure if it's the best way, but:

aHash = Hash.new
('A'..'Z').each_with_index {|k, v| aHash[k] = v }

will work.

regards,
-joe