From: Isak <isak.hansen@...>
Date: 2006-08-24T01:45:08+09:00
Subject: Re: Call functions of superclass

Julian 'Julik' Tarkhanov wrote:
> 
> On 23-aug-2006, at 17:39, James Edward Gray II wrote:
> 
>> Try the correction above.  ;)
> 
> Actually I am curious to know:
> 
> class Parent
>    def something
>    end
> 
>    def another
>        # do foo
>    end
> end
> 
> class Child < Parent
>    def something
>        super.another # call _another_ instance method BUT of the 
> superclass, not one's own
>    end
> 
>    def another
>        # do bar instead of foo
>    end
> end
> 
> is that at all possible somehow? Just out of curiosity.


Don't have too much exposure to Ruby myself, but spent some time on 
#ruby-lang asking getting answers to this and the OP's questions a 
couple of days ago.

AFAIK 'super' simply invokes the overriden method, so your example would 
be calling the method 'another', on whatever object is returned by 
Parent::something().

I don't think there's any way to refer to an object as if it had the 
base classes' type, but you can alias the method before overriding it:

class Child < Parent

   def something
     old_another
   end

   alias :old_another :another
   def another
     # overriding the old one
   end
end


Isak


> --Julian 'Julik' Tarkhanov
> please send all personal mail to
> me at julik.nl
> 
> 
>