From: Logan Capaldo <logancapaldo@...>
Date: 2006-08-14T03:43:43+09:00
Subject: Re: ruby equiv of perl pos


On Aug 12, 2006, at 4:33 PM, snacktime wrote:

> Or to be more exact, how would I do the following in ruby?
>
> while ($string =~ /\0/g) {
>    $new_string .= sprintf '\%o', (pos $string) - 1;
> }
>

if perldoc -f pos is describing what pos does in this case,

new_string = ""
while pos = string =~ /\0/g
   new_string << "%o" % (pos - 1)
end