From: gga <GGarramuno@...>
Date: 2006-08-13T07:50:13+09:00
Subject: Re: ruby equiv of perl pos


> Another idea:
>
> string = "one\0two\0threeeeeee\0"
> result = ''
> string.scan(/\0/) do
>    result << '\%o' % $`.length
> end

This is simpler to write, but will be slower on longer strings.

#!/usr/bin/env ruby

@string = "\0\0\0asda\0\0\0sdasd" * 5000

def test_a
  result = ''
  pos = 0
  while pos = @string.index( /\0/, pos )
    match = Regexp.last_match
    pos += match.size
    result <<  '\%o' % (pos - 1)
  end
  return result
end


def test_b
  result = ''
  @string.scan(/\0/) do
    result << '\%o' % $`.length
  end
  return result
end

require 'benchmark'

Benchmark.benchmark() { |x|
  x.report('a:') { test_a }
  x.report('b:') { test_b }
}