From: Robin Stocker <robin@...>
Date: 2006-08-13T07:14:51+09:00
Subject: Re: ruby equiv of perl pos

snacktime wrote:
> Or to be more exact, how would I do the following in ruby?
> 
> while ($string =~ /\0/g) {
>    $new_string .= sprintf '\%o', (pos $string) - 1;
> }

Another idea:

string = "one\0two\0threeeeeee\0"
result = ''
string.scan(/\0/) do
   result << '\%o' % $`.length
end
puts result  #=> \3\7\22

   Robin