From: gga <GGarramuno@...>
Date: 2006-08-13T07:05:11+09:00
Subject: Re: ruby equiv of perl pos

snacktime ha escrito:

> Or to be more exact, how would I do the following in ruby?
>
> while ($string =~ /\0/g) {
>     $new_string .= sprintf '\%o', (pos $string) - 1;
> }

#!/usr/bin/env ruby

new_string = ''
string = "\0\0\0asda\0\0\0sdasd"

pos = 0
while pos = string.index( /\0/, pos )
  match = Regexp.last_match
  pos += match.size
  new_string <<  '\%o' % (pos - 1)
end

puts new_string