From: Stefan Rusterholz Date: 2006-08-12T01:02:57+09:00 Subject: Re: Fix for rational.rb (accepting Rationals as num/den) Whoops, that was the old code snippet... def Rational(a, b = 1) Rational.reduce(*Rational.normalize(a,b)) end class Rational < Numeric # normalizes numerator/denominator to non-rationals def Rational.normalize(a,b) if a.kind_of?(Rational) then if b == 1 then return [a.nominator, a.denominator] elsif b.kind_of?(Rational) then return [a.numerator*b.denominator, a.denominator*b.numerator] else return [a.numerator, a.denominator*b] end elsif b.kind_of?(Rational) then if a == 1 then return [b.denominator, b.nominator] else return [a*b.denominator, b.numerator] end else return [a,b] end end def Rational.new!(num, den = 1) new(*Rational.normalize(num,den)) end end Should work a bit better ;-) -- Posted via http://www.ruby-forum.com/.