From: gwtmp01@...
Date: 2006-08-11T10:56:45+09:00
Subject: Re: Referring to an instance method using a variable


On Aug 10, 2006, at 9:33 PM, Jos Backus wrote:
> This is what I have come up with:
>
>     lizzy:~% cat rtest
>     OPS = {
>       '=' => proc { |a, b| return a == b ? 1 : 0 },
>       '==' => proc { |a, b| send(:equals, a, b) },
>     }
>
>     def equals(a, b)
>       return a == b ? 1 : 0
>     end
>
>     puts OPS['='].call(1, 1)
>     puts OPS['=='].call(1, 2)
>     lizzy:~% ruby rtest
>     1
>     0
>     lizzy:~%

Is there supposed to be a semantic difference between the '=' and '=='
operator in what you are trying to accomplish or are you just trying to
implement '=' as a proc and '==' as a method?

Does this help at all?

def equals(a, b)
   return a == b ? 1 : 0
end

OPS = {
   '=' => proc { |a, b| return a == b ? 1 : 0 },
   '==' => method(:equals),
}

puts OPS['='].call(1, 1)
puts OPS['=='].call(1, 2)


Gary Wright