From: dblack@...
Date: 2006-08-07T10:25:06+09:00
Subject: Re: Issue with regex

Hi --

On Mon, 7 Aug 2006, junkone1@gmail.com wrote:

> I have a string
> <A
> HREF="http://stockcharts.com/h-sc/ui?s=ACN.TO&id=p41804099534&a=81626743&listNum=30">
> <IMG SRC="/images/ico_candle_on.gif" BORDER=0 ALT="Default
> SharpChart"></A><A HREF="/webcgi/wb.exe?gall.web+ACN.TO"><IMG
> SRC="/images/ico_trendline_on.gif" BORDER=0 ALT="Gallery Page"></A><A
> HREF="/def/servlet/SC.pnf?c=ACN.TO,P&listNum=30"><IMG
> SRC="/images/ico_pnf_on.gif" BORDER=0 ALT="P&amp;F Chart"></A>
>
>
>
>
> When i use the Regulator to create a regex it matches. my sample is
> "http(.)+["]
>
> It returns
> "http://stockcharts.com/h-sc/ui?s=ACN.TO&id=p41804099534&a=81626743&listNum=30">
>
> However when i use ruby, it returns
> When i use ruby with syntax  a.scan(/"http(.)+["]/)
>
> It returns [["t"]]
>
> can someone help determine what error i am doing

When you use parenthetical captures, String#scan returns successive
arrays of those captures.  In the case of your scan, you've matched
the string once, and captured "t" in the first () group.

If you want a substring that starts with "http and ends with ", you
can do:

   a[/"http[^"]+"/]


David

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